Rewriting a Call Pattern in Expressway for Cisco UCM Integration: Exam Answer
Question
A call is sent by Cisco UCM to Expressway with a URI of 75080001@expc1a.pod8.test.lab.
If (7508')@expc1a\.pod8\.test\.lab.* is the pattern string, what would be the replacement string of the transform in Expressway to re-write the call so that it becomes 75080001@conf.pod8.test.lab?
Answers
Explanations
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A. B. C. D.C.
This question is testing your knowledge of call routing and transformation in Cisco Expressway. The scenario is that a call is being sent from Cisco Unified Communications Manager (UCM) to Cisco Expressway with a URI of 75080001@expc1a.pod8.test.lab. The objective is to re-write the call so that it becomes 75080001@conf.pod8.test.lab using a transform.
The pattern string given is (7508')@expc1a.pod8.test.lab.*. Let's break down this pattern string:
- (7508
) - This is a capturing group that matches the digits 7508 followed by any character (represented by thesymbol). The purpose of the capturing group is to extract the digits 7508 so that they can be used in the replacement string. - @expc1a.pod8.test.lab - This matches the literal string @expc1a.pod8.test.lab.
- .* - This matches any number of characters after the @expc1a.pod8.test.lab string.
The replacement string must be \1@conf.pod8.test.lab, which includes a reference to the first capturing group (\1) and the new domain name conf.pod8.test.lab.
The correct answer is therefore C. \1@conf.pod8.test.lab.
