"Initializing a Locale Variable: Exam 1Z0-809"

DE.

Of the options given, the two correct code blocks to initialize a Locale variable are:

B. Locale loc2 = Locale.getInstance("ru"); E. Locale loc5 = new Locale ("ru", "RU");

Here's why:

A. Locale loc1 = "UK"; This code block is incorrect because it attempts to assign a string literal to a Locale variable. The compiler will not allow this type of assignment, and will generate an error. To create a Locale object, one of the Locale class factory methods or the constructor should be used.

B. Locale loc2 = Locale.getInstance("ru"); This code block is correct because it calls the Locale.getInstance() method to create a Locale object with the specified language code "ru". The method will automatically handle the conversion of the language code to the appropriate case, and will return a Locale object with the language set to "ru".

C. Locale loc3 = Locale.getLocaleFactory("RU"); This code block is incorrect because there is no getLocaleFactory() method in the Locale class. This is likely a typo or a misunderstanding of the Locale class methods.

D. Locale loc4 = Locale.UK; This code block is incorrect because it attempts to assign a static field of the Locale class to a Locale variable. While this is a valid way to obtain a Locale object with the language and country set to the default values for the UK, it is not a method call, and thus is not one of the correct code blocks.

E. Locale loc5 = new Locale ("ru", "RU"); This code block is correct because it creates a new Locale object with the specified language code "ru" and country code "RU". The Locale constructor takes two String arguments: the language code and the country code, in that order. By passing in "ru" and "RU", respectively, the code creates a Locale object representing the Russian language as spoken in Russia.