Question 511 of 952 from exam 200-125: Cisco Certified Network Associate Exam

# Question 511 of 952 from exam 200-125: Cisco Certified Network Associate Exam

### Question

Given an IP address 172.16.28.252 with a subnet mask of 255.255.240.0, what is the correct network address?

### Explanations

Click on the arrows to vote for the correct answer

A. B. C. D.

A

For this example, the network range is 172.16.16.1 - 172.16.31.254, the network address is 172.16.16.0 and the broadcast IP address is 172.16.31.255.

To determine the network address for the given IP address and subnet mask, we need to perform a bitwise AND operation between the two.

Here are the steps to perform this operation:

1. Convert the IP address and subnet mask to binary form.

IP address: 172.16.28.252 Binary: 10101100.00010000.00011100.11111100

Subnet mask: 255.255.240.0 Binary: 11111111.11111111.11110000.00000000

1. Perform a bitwise AND operation between the binary representations of the IP address and subnet mask.

## 10101100.00010000.00011100.11111100 (IP address) AND 11111111.11111111.11110000.00000000 (subnet mask)

10101100.00010000.00010000.00000000

1. Convert the result of the bitwise AND operation back to decimal form to obtain the network address.

Binary: 10101100.00010000.00010000.00000000 Decimal: 172.16.16.0

Therefore, the correct network address for the given IP address and subnet mask is 172.16.16.0, which is option A.