Maximizing Subnets with a Subnet Mask for Cisco Certified Network Associate Exam 200-125

# Network Address and Subnet Mask for Same Network and Maximum Subnets

### Question

You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the max number of subnets.

### Explanations

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A. B. C. D. E.

A

To determine the correct subnet mask that allows all three web servers to be on the same network while providing the max number of subnets, we need to perform the following steps:

Step 1: Determine the maximum number of hosts required In this scenario, we know that there are three web servers that need to be on the same network. To determine the maximum number of hosts required, we add 3 (for the web servers) + 2 (for the network and broadcast addresses) = 5.

Step 2: Determine the number of subnets required To provide the maximum number of subnets, we need to use the subnet mask that provides the highest number of bits for the network portion of the address. The number of subnets required can be calculated as 2^n, where n is the number of subnet bits. Since we want to provide the maximum number of subnets, we need to use the subnet mask with the highest number of bits for the network portion of the address. In this case, we can use 3 bits for the subnet, which will provide us with 8 subnets (2^3).

Step 3: Determine the subnet mask To determine the subnet mask, we need to convert the number of bits used for the network portion of the address into decimal format. In this scenario, we are using 3 bits for the subnet, which gives us a subnet mask of 11111111.11111111.11111111.11111000 or 255.255.255.248.

Step 4: Determine the network address To determine the network address, we take the given IP address (in this case, we do not have an IP address provided) and apply the subnet mask we determined in Step 3. In this case, any IP address that falls within the range of 192.168.252.0 to 192.168.252.7 (with a subnet mask of 255.255.255.248) would be on the same network as the three web servers.

Based on the above steps, the correct answer is A. 192.168.252.8 255.255.255.248, which provides 8 subnets and allows all three web servers to be on the same network.