Given an IP address 172.16.28.252 with a subnet mask of 255.255.240.0, what is the correct network address?
Click on the arrows to vote for the correct answerA. B. C. D.
For this example, the network range is 172.16.16.1 - 172.16.31.254, the network address is 172.16.16.0 and the broadcast IP address is 172.16.31.255.
To determine the network address for the given IP address and subnet mask, we need to perform a bitwise AND operation between the two.
Here are the steps to perform this operation:
IP address: 172.16.28.252 Binary: 10101100.00010000.00011100.11111100
Subnet mask: 255.255.240.0 Binary: 11111111.11111111.11110000.00000000
Binary: 10101100.00010000.00010000.00000000 Decimal: 172.16.16.0
Therefore, the correct network address for the given IP address and subnet mask is 172.16.16.0, which is option A.